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Stereochemistry · Chemistry

Geometrical Isomerism: Cis–Trans & Allenes Simulation

Build an alkene and try to twist its C=C: watch the π overlap fall to zero at 90°. Read cis/trans and E/Z, see why an even number of cumulated C=C makes an allene chiral, and lock or free the rings of biphenyls and terphenyls.

Interactive virtual lab · no download · works on phones and laptops

Chapter
Isomerism
For
Class 11 · Class 12 · JEE · NEET
Time
~15 min

Geometrical Isomerism: Cis–Trans & Allenes is a Pro simulation

Pro opens all 125 virtual labs — 483 simulations with guides and quizzes.

How to use it

  1. 1Cis–trans & E/Z: pick a preset or choose the four groups, then tick “Twist” and “Flip”.
  2. 2Turn on CIP priorities to see why a cis alkene can be E.
  3. 3Allenes: change the number of C=C and the end groups; show the mirror image and try to lay it on.
  4. 4Biphenyls & terphenyls: change the ortho groups and watch the rings lock or spin.

What to notice

  • Geometrical isomers need restricted rotation AND two different groups on each carbon.
  • Twisting a C=C breaks the π bond (about 260 kJ/mol), so cis and trans do not interconvert.
  • Flipping the whole molecule never turns cis into trans.
  • cis is not always Z: E/Z compares CIP priorities, cis/trans compares like groups.
  • Even number of cumulated C=C: ends perpendicular, optical isomers. Odd: ends coplanar, cis/trans.
  • Bulky ortho groups lock a biphenyl non-planar; it is chiral only if both rings are unsymmetrical.
  • A locked terphenyl's outer rings are coplanar: cis/trans, never optical.

For teachers

A ready-made teaching kit comes with this lab

  • Lesson plan

    23 min, 4 steps

  • Ask the class

    4 questions with answers

  • Quick quiz

    7 questions, printable

  • Key formulas

    3 formulas

About the Geometrical Isomerism: Cis–Trans & Allenes simulation

Geometrical (cis–trans) isomerism appears when rotation about a bond is restricted and each end carries two different groups. A C=C double bond is rigid because its π bond needs the p orbitals on both carbons to stay parallel: twisting one end by 90° destroys the overlap, which costs about 250–270 kJ/mol. So cis-but-2-ene and trans-but-2-ene are separate compounds. When groups are not repeated across the bond, or when cis/trans disagrees with priorities, the E/Z system decides: Z when the higher-priority groups (by CIP rules) are on the same side, E when they are opposite.

This geometrical isomerism simulation lets you build an alkene from any four groups, twist the C=C slowly and watch the π overlap fall to zero, flip the whole molecule to see that cis stays cis, and turn on CIP priorities to see why cis-2-bromobut-2-ene is E. The Allenes tab shows why an even number of cumulated double bonds puts the two ends in perpendicular planes (optical isomers with no chiral carbon) while an odd number keeps them in one plane (cis/trans). The Biphenyls tab locks or frees the rings with ortho groups: planar or non-planar, chiral biphenyls and cis/trans terphenyls.

Also covers: geometrical isomerism, cis trans isomerism, e z nomenclature, e/z, restricted rotation, allene, cumulene, axial chirality, biphenyl, atropisomerism, terphenyl, planar and non planar, ortho substituted biphenyl, optical activity without chiral carbon.

Frequently asked questions

Why does 1,1-dichloroethene show no geometrical isomerism?

One carbon carries two identical chlorine atoms, so swapping the groups on that carbon gives the same molecule. Each doubly bonded carbon must carry two different groups.

Is cis always the same as Z?

No. cis/trans compares identical groups, E/Z compares the higher-priority groups. In 2-bromobut-2-ene the two CH₃ groups are cis, but Br outranks CH₃, so the molecule is E.

Why is an allene like penta-2,3-diene optically active without a chiral carbon?

The two terminal carbons hold their groups in perpendicular planes. With two different groups at each end the molecule has no plane or centre of symmetry, so it and its mirror image are enantiomers.

When is a biphenyl optically active?

When bulky ortho groups stop rotation about the ring–ring bond (the rings stay perpendicular) and each ring carries two different ortho groups, as in 6,6′-dinitrobiphenyl-2,2′-dicarboxylic acid.